C. Queen
https://codeforces.com/problemset/problem/1143/C
부모 노드를 respect하지 않고, 자식 노드도 나를 respect하지 않으면 해당 노드를 없앤다.
dfs를 root부터 돌면서, 위 조건을 충족하는 노드를 찾으면 된다.
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 | #include <bits/stdc++.h> using namespace std; const int N = 100005; vector<int> ans, vc[N]; int res[N]; int n, root, in ,respect; bool dfs(int v) { bool on = false; for (int i = 0; i < vc[v].size(); i++) { if (dfs(vc[v][i])) on = true; } if (!on && res[v] == 0) ans.push_back(v); if (res[v] > 0) return true; else return false; } int main() { ios::sync_with_stdio(0); cin.tie(NULL); cout.tie(NULL); cin >> n; for (int i = 1; i <= n; i++) { cin >> in >> respect; if (in == -1) root = i; else { vc[in].push_back(i); } if (respect == 0) res[i] = 1; } dfs(root); if (ans.size() > 0) { sort(ans.begin(), ans.end()); for (int i = 0; i < ans.size(); i++) cout << ans[i] << ' '; } else cout << -1; return 0; } | cs |
'Competition > codeforces' 카테고리의 다른 글
Codeforces Round #513 by Barcelona Bootcamp (rated, Div. 1 + Div. 2) A. Phone Numbers (0) | 2019.04.03 |
---|---|
Codeforces Round #523 (Div. 2) A. Coins (0) | 2019.04.03 |
Codeforces Round #550 (Div. 3) E. Median String (0) | 2019.04.01 |
Codeforces Round #550 (Div. 3) D. Equalize Them All (0) | 2019.04.01 |
Codeforces Round #550 (Div. 3) C. Two Shuffled Sequences (0) | 2019.04.01 |